ricky
1
I made a simple Macro for get the list top10
\define list-top10(myfilter)
<$list filter="$myfilter$ +[limit[10]]" variable="current">
<<current>><br>
</$list>
\end
<<list-top10 "[!is[system]]">>
But when I transfer the Macro to Procedure, it doesnt work.
\procedure list-top10(myfilter)
<$list filter="<<myfilter>> +[limit[10]]" variable="current">
<<current>><br>
</$list>
\end
<<list-top10 "[!is[system]]">>
How to fix it correctly?
Because you cant use the old form of substitution you need to use a way to treat the value a a filter.
\procedure list-top10(myfilter)
<$list filter="[subfilter<myfilter>] +[limit[10]]" variable="current">
<<current>><br>
</$list>
\end
<<list-top10 "[!is[system]]">>
You dont need to change it, but its good to learn
Within the $list filter, you can use the [subfilter<varname>] syntax, like this:
<$list filter="[subfilter<myfilter>] +[limit[10]]" variable="current">
enjoy,
-e