How do I close a specified tiddler?

1

I am using a list where I want a close button for each item. How would be able to close the specified tiddler in the list.

Below is what I have tried, but it’s only closing <<currentTiddler>>:

<$list filter="my-filter" variable="my-list-item">
  <$button tiddler=<<my-list-item>> message="tm-close-tiddler">
  {{$:/core/images/close-button}}
  </$button>
  <$link to=<<my-list-item>>/>
</$list>
2

I have a macro I include after a list item, where each tiddler becomes currentTiddler

\define close-button()
<$button message="tm-close-tiddler" tooltip="Close - item open in story" aria-label={{$:/language/Buttons/Close/Caption}} class="tc-btn-invisible">x</$button>
\end

<$list filter="[tag[TableOfContents]]">
   <$link/> <<close-button>><br>
</$list>
  • This works and will close tiddlers If Open

However if your filter lists items also not open a condition so you test if it is open first befor displaying the close button makes sense.

I do this in this history sidebar. warning under redevelopment,

history-sidebar.json (2.8 KB)

3

You were almost there!

As documented here: https://tiddlywiki.com/#WidgetMessage%3A%20tm-close-tiddler, the tm-close-tiddler message uses param (not tiddler) to specify the title to be closed. Thus, your code should be:

<$list filter="my-filter" variable="my-list-item">
   <$button message="tm-close-tiddler" param=<<my-list-item>>>
      {{$:/core/images/close-button}}
   </$button>
   <$link to=<<my-list-item>>/>
</$list>

Alternatively, if you omit variable=my-list-item in the $list widget (i.e., allow it to use the default variable, currentTiddler), you can simplify it to just:

<$list filter="my-filter">
   <$button message="tm-close-tiddler">
      {{$:/core/images/close-button}}
   </$button> 
   <$link/>
</$list>

Note that the above code uses the value of currentTiddler as the default parameter for the $link widget as well.

enjoy,
-e