john.edw_gmail.com | 2023-11-01 23:42:21 UTC | #1

How can I get the following output linking items with the appropriate group based on the fieldname?
```
group1 name
item1stuff

group2 name
item2 stuff
```
This is close but lists all item-x fields under each group. Unknown number of group|item pairs per tid.
```
<$list filter="[<currentTiddler>fields[]prefix[group]]" variable="thisfield">
<$view field=<<thisfield>>/><br>
<$list filter="[<currentTiddler>fields[]prefix[item]]" variable="thisitem">
<$view field=<<thisitem>>/><br>

</$list>
```
![image|690x247, 75%](upload://q1lhmSVKzBxNBrzjFXSwkWNic16.png)

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EricShulman | 2023-11-02 03:14:30 UTC | #2

Try this:
```
<$list filter="[<currentTiddler>fields[]prefix[group]]" variable="thisgroup">
   <$view field=<<thisgroup>>/><br>
   <$let itemprefix={{{ [[item-]] [<thisgroup>split[-]nth[2]] +[join[]] }}}>
   <$list filter="[<currentTiddler>fields[]prefix<itemprefix>]" variable="thisitem">
      &emsp; <$view field=<<thisitem>>/><br>
   </$list>
   </$let>
</$list>
```
Notes:
* Inside the outer `$list` widget, we construct the desired "item-#" prefix by using a "filtered transclusion" to join together the literal text "item-" and the number for the current group, which we extract from the `thisgroup` variable using `split[-]` and `nth[2]` filter operators.
* We can then use the constructed prefix in the second `$list` widget's filter.
* I added an `&emsp;` (a full em-space HTML character) to provide indentation for the item output

enjoy,
-e

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